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TPS75101QPWP Query

Pradap Raj
Prodigy 130 points

Hi,

  We are using TPS75101QPWP LDO in our new design where we need 2,5V output. Here we are using 3.3V voltage as input to generate 2.5V output. While seeing in the datasheet operating condition, it is mentioned test condition for 2.5V is only 3.5 V < VIN < 5.5 V. So is there any issue if we use 3.3V input to generate 2.5V? Please let us know your comment.

 

Regards,

Pradap

  • 0
    TI__Guru**** 150750 points

    This comment is merely the test conditions for output voltage accuracy.  The accuracy is only guaranteed when Vin > Vout + 1V.  The note on page 3 says:

    To calculate the minimum input voltage for your maximum output current, use the following equation: V

     

    IN(min) = VOUT(max) + VDO(max load)"

    Since the dropout is so low, it can work with your Vin.

    What is your output current requirement?  We have other, newer parts that might be better.

  • 0 in reply to Chris Glaser
    Prodigy 130 points

    In page 4 of TPS75101 datasheet, i can see the Note 1 "Minimum VIN = (VOUT + 1 V) or 2.7 V, whichever is greate" .Our output current requirement is around 1A. Since we are using this same part in our other boards, we doesn't want to change this part.

  • 0 in reply to Pradap Raj
    TI__Guru**** 150750 points

    Yes, that note 1 on page 4 applies to the Vout accuracy spec, which has a (1) by it.  It also applies to the line reg and PSRR specs on that page.  Vout + 1V is an industry standard performance point for measuring LDO parameters.

    The minimum Vin for the device to operate and output the correct voltage is noted on page 3 in that note 1.  Notice that this note 1 applies to an input voltage range.  This is the parameter you are asking about.