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LM3410: Checking if I understand power dissipation in my LM3410 design

Part Number: LM3410

Hi, 

      I'm doing a new board based on the LM3410, basically the LM3410X SEPIC demo board, I'd like to shrink it a little too so I want to make sure I'm understanding the power dissipation paths.  

LEDs

LED Vvf = 3V and I = 0.35A. I'll do a string of 8 which is 24V @ 0.35A

That makes output power 8.4W

Input Power

My input will be 5V. I don't know the efficiency but if it was a magically 100% that would mean I needed an input current of 1.68A.

Power Dissipation by LM3410

The LM3410 has a Rdson of 0.33 Ohm so at 1.68A that's 0.93Watts (way more than the SOT package can handle).  I assume I'll have to do a little thermal simulation here and use the LM3410XMFX with the DAP.

Inductors

I think L1 takes the worst of it. The Coilcrafts you use have a 0.043Ohm DCR, but even at 1.5x the input current of 1.68A that's 0.273W.  L2 I think only takes the load current so that would be 0.35A ^2 * 0.043 = 5mW.

Catch Diode

The catch diode from your design has a Vfw of 0.32 so at 0.35A load current that's 112mW dissipation.

Am I on the right track here despite not calculating  the efficiency? Did I miss anything important?  Also it looks like the SoT part is a no-go because it has a 400mW maximum power dissipation, and I assume the smaller parts power dissipation will be dependent on the size of GND plane I attach it to (and air flow etc.).

Thanks!

  • I think the calculation is ok. You may set efficiency as 85% for calculation, or you can just estimate the efficiency as you calculated most of the power loss already.

    You are right that SOT part is not good option for this design considering thermal.