• State TI Thinks Resolved
  • Locked Locked
  • Replies 2 replies
  • Answers 1 answer
  • Subscribers 63 subscribers
  • Views 121 views
  • Users 0 members are here
Support feedback
Options
Options
Similar topics

This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

TPS54719: TPS54719RTER

Ashvin Patil
Prodigy 30 points
Part Number: TPS54719
Other Parts Discussed in Thread: TPS62811-Q1, TPS628501

Hi,

We are using the TPS54719RTER buck converter for 1.8V and 1V for our application having two FPGAs (XC7S50-1FGGA484C, Spartan-7 series ).

Following is the requirement,

For 1V

Vin -   5V

Vout - 1V

Iout - 200mA  (Static load)

total load capacitance -  120uF  (decoupling capacitors) 

For 1.8V

Vin -   5V

Vout - 1.8V

Iout - 200mA  (Static load)

total load capacitance -  540uF  (decoupling capacitors) 

We need to know the how much inrush current will drive through the Input supply and whether it is reliable solution, possibly share waveform for the same.

We simulated the above requirement in Webench but could not able to find to simulate with adding capacitive load and with dynamic load.

For reference, attach the circuit.

Thanks.

  • 0
    TI__Guru*** 145830 points

    Hi,

    The TPS54719 is a very old device.  Why do you want to use it?

    With your very low load currents, you can use the TPS628501.  Or, the larger TPS62811-Q1 supports a larger capacitive load.

    The inrush current for any buck can be estimated by Iout = Cout * Vout / Tss + Iload.  The inrush into the output is the load current during soft start + the current required to charge the output caps.  Then, convert this output current to an input current with: Iin = Iout * Vout / (Vin * eff.)

    Thanks,

    Chris

  • 0 in reply to Chris Glaser
    Prodigy 30 points

    Thank you. Will consider the suggested part.