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BQ79616-Q1: BQ79616 UART RX Pin: Direct Pull-Up to CVDD or Through Resistor?

Part Number: BQ79616-Q1
Other Parts Discussed in Thread: BQ79616, USB2ANY

Hello,

I am designing a BMS with the BQ79616 and I'm currently setting up the UART communication lines, specifically for the RX pin.

Based on the datasheet's instructions:

"The UART interface requires that RX is pulled up to CVDD through a resistor on the base device. The RX is pulled up on the device side. Do not leave RX unconnected. Ensure RX is connected directly to CVDD for stack devices."

I am seeking clarity on the following:

  1. Should I pull up the RX pin directly to CVDD without a resistor, or should I use a resistor for the pull-up?
  2. If a resistor is recommended, what would be the appropriate value for it? Would a 100k resistor be suitable?

Thank you for your guidance on this matter.

My design is below.

Best regards, Batuhan

  • Hi Batuhan,

    Should I pull up the RX pin directly to CVDD without a resistor, or should I use a resistor for the pull-up?

    A resistor is recommended if you intend to use RX and TX for UART communication. Shorting RX to CVDD will disable the use of RX and TX pins for UART.

    If a resistor is recommended, what would be the appropriate value for it? Would a 100k resistor be suitable?

    A 100k resistor is suitable. On the EVM, we use a 100k resistor between RX and CVDD. To disable UART, the EVM has Jumper J1 which can short RX and CVDD when populated.

    Regards,

    David

  • Thank you for your response. I referance EVM. what about RX MC can you explain the 100R?

  • Hi Batuhan,

    If you are referencing RX_C:

    This is because J3 is for an FTDI cable which is a second way to talk to the EVM. In the case that the user is using both a USB2ANY and FTDI cable, the 100 ohm resistor is to limit the current between the two voltage sources (USB2ANY's 5V line & FTDI's 5V line). If you are using only 1 form of UART communication, then you do not need this resistor.

    Regards,

    David