BQ76930: BQ76930 How to calculate the current accuracy?

Hello Star,

Assuming we ignore non-linearity and offset. The current error would be determined by the gain error. 

Datasheet gives a worst-case gain error of 1.5% of the full scale range of the coulomb counter. the full range is -270-mV to 270-mV. So, 1.5% of this range would correspond to ~4-mV of gain error across the whole range. This would be the error at the edges of the voltage range of the coulomb counter, so at ~270-mV.

Let's assume that there is a 2000-mA current flowing through, if we assume the worst gain error is 1.5%, this means that the measurement could be read as 2030-mA. Although this depends on the sense resistor used. The current error due to gain will never be more than 1.5%.

Offset and INL errors are given with respect to LSB's. Which is given as 8.44-uV per LSB. 

Best Regards,

Luis Hernandez Salomon