This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

TPS65987D: Thermal Dissipation for FET Drain Pads

Part Number: TPS65987D


Hello team,

On the datasheet, it says "When doing thermal calculations it is recommended to use the worst case 200°C/W which will give a set of six vias a thermal resistance of approximately 33℃/W".

Does this mean that thermal resistance of each vias are 200℃/W, and when used with 6 vias, it would be 200℃/W / 6 = 33℃/W? Is this understanding correct?

Also I want to confirm the Junction temp of the FET calculation. Could you please check the equations below?

When current through FET was 2.7A, where FET on resistance = 33mΩ, Rθjc(bot_FET) = 5.6℃/W.

Power dissipation = 2.7A x 2.7A x 33mΩ = 0.24W

Tj(bot_FET) = 0.24W x (33℃/W + 5.6℃/W) + 50℃ = 59.264℃

Best Regards,
Kei Kuwahara

  • Thermal resistance of via would depend on your PCB design (size of copper used) and via size you use. In the reference layout  thermal resistance is ~200℃/W.

    For you calculation seems like you as assuming PCB temperature to be 50C. Looks ok to, junction to Ambient should not be significant here.