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LM25148: Standby and sleep current

Koyo Asaishi
Intellectual 1810 points
Part Number: LM25148

Hi team

I want to know the detail between standby current and sleep current of LM25148.
Test condition of standby current is 0.5V<Ven<1, this would mean device isn't active and output is 0V. Test condition of sleep current is 1.03V<Ven<42, this mean device is enabled.

Why is standby current higher than sleep current? Standby seems device is disabled so the current should be between shutdown and sleep.

By the way, test condition of standby current is typo as 0.5V>Ven<1V.

Best regards
koyo

  • 0
    TI__Mastermind 31490 points

    Hello Koyo,

    Standby mode: "When the enable voltage is between 0.5 V and 1 V, the LM25148 is in standby mode with the VCC regulator active but the controller is not switching. In standby mode, the non-switching input quiescent current is 124-μA typical."  All internal circuits are active.

    To disable the device and draw minimal currents, you need to disable the device, do not put in standby.

    Sleep Mode description: " During no-load or light-load conditions, the output capacitor discharges very slowly. As a result, the compensation voltage does not demand the driver output pulses on a cycle-by-cycle basis. When the LM25148 controller detects 16 missed switching cycles, it enters sleep mode and switches to a low IQ state to reduce the current drawn from the input"

    In other words, in the intervals when VOUT is an acceptable level, all internal circuits are put into a low IQ operation mode, most internal circuits are off in this interval. 

    Hope this helps.

    David.