My main doubt is :
I need to develop an IP camera which is :
- IEEE 802.3xx compliant,
- Work with an active PoE PSE @ 37V-60V,
- Work with a passive PoE (without PSE) @ 24V
- There is only one way to supply the IP camera : RJ45 cable.
In the datasheet (TPS23730), it can be read that there is APD and PPD pin .
As I explained before, in my case, there is only one power source, and it comes from the Ethernet cable.
So, the APD pin is not used.
However, there is the PPD pin.
So, if I put the PPD pin to VSS through a pull-down resistor
- the TPS23730 will be turn on @ 24V and the DC/DC too ?
- Will the UVLO protection disabled ? Even when the PSE is an active one ?
- Would we compliant with IEEE standard or the PPD pin need to be left open in order to be compliant ?
If you confirm the last question, if I can turn on the TPS @ 24V , will this mean that we are no longer compliant with IEEE 802.3 ?
(maybe because of voltage level input => not in the range of 37V – 60V ? )
For an IP camera wich is only supply with the Ethernet cable, is it possible to used only a buck instead of a flyback ?
What about the Handshaking Protocol ?
As we can see, the voltage levels for the handshaking protocol are under 20.5V.
What if we supply the TPS23730 with for example 16V ? for example 24V ?
If PPD pin is tie to VSS , what is going on with the inrush phase ?
- Will it be disabled ?
- Even when a PSE active who is compliant IEEE 802.3xx ?
Can be we IEEE 802.3xx compliant when an active PSE is used and at the same time, working with a voltage (typically 24V) of a PSE passive without changing the PCB ?
If PPD pin is tied to VSS, the compliance with IEEE standard is lost ?
Thank you.