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CSD95496QVM: Inductor value selection

Part Number: CSD95496QVM

Hi,

Iam using CSD95496QVM in my design. Can anyone help me out how to choose the inductor value.

Thanks 

Harika

  • Hello, 

    A good compromise, the inductor current ripple is 10% to 30% of the load current IOUT. The formula is L = (VIN - VOUT)*(VOUT/VIN)*(1/(K*Fsw)).

    Where K is 0.1 to 0.3, Fsw is the switching frequency. I hope that answers your question.

    Regards