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TPS2384

Nick Carter
Intellectual 830 points
Other Parts Discussed in Thread: TPS2384

Hi,all

I'm using TPS2384 in my design. The typical voltage of POE is 48V.

I know that Port P N monitor the voltage of PD. Does the port P N provide 48V to PD? Or there are some other pins providing power supply to PD.

How does it accomplish the management of power supply? TPS2384 in our design is working in PMM Mode.

Thank you

Nick

 

  • 0
    TI__Mastermind 42795 points

    The "P" terminal of the TPS2384 is a monitor only and the 48V power supply in the PSE system sources the PD current. Refer to the single port block diagram on pg 6 of the datasheet which shows this. The "N" terminal of the TPS2384 can be viewed as the controlling terminal and can operate in a linear fashion depending on the port function (see table 6 function bits D3..D0). This terminal sinks the PD and 48V port current.

  • 0 in reply to Eric Wright
    Prodigy 40 points
    Hello -

    I am using the TPS2384 in a design (auto mode only). All P and N port pins are near ground. Shouldn't P be at 48V? I have +48V at pin 60. The 10V, 6.3V, 3.3V and 2.5V supply pins look okay. Sync out looks good. I carefully compared my design with the TPS2384 Eval Module schematic and cannot see what is wrong?

    Thank you.
  • 0 in reply to Jay Perrin
    TI__Genius 15685 points

    Hi Jay,

    The P pin should be connected to +48V and it is not internally connected to 48V. Figure 6 at  page 14 in TPS2384 datasheet shows a system block diagram.

    Best regards,

    Penny

  • 0 in reply to Penny Xu
    Prodigy 40 points

    Penny,


    Thanks. It's working now. I am not using the AC disconnect function. Is there any advantage to using D1 as shown in the SLVA233A app note on page 10 and 11? Or is it okay to directly connect P1 - P4 to +48V?


    Thanks you,


    Jay

  • 0 in reply to Jay Perrin
    TI__Genius 15685 points
    Hi Jay,

    Yes. You can connect P to +48V directly. The schottky diode is needed only when you use AC disconnect function. The diode blocks the AC signal and AC signal will not be filtered by the input cap.

    Best regards,
    Penny