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TPS23882B1EVM-008: TPS23882B1

Part Number: TPS23882B1EVM-008
Other Parts Discussed in Thread: TPS23882B

Tool/software:

Hi,

In my design we are using TPS23882B part, We are facing issue on GATE output drive on PSE Controller(TPS23882B). we measure voltage on GATE pins(GAT1 - GAT8) is 0V.

Settings are in Autonomous Mode, disable I2C.

Kindly suggest how to drive GAT voltage, please check below schematic for your reference.

  • Hi TI Team,

    Any updates? kindly support us.

  • Hi Prabhu,

    From the schematic, you show Pin 52 as NC. Pin 52 is the autonomous control pin which uses a shot current to determine the operating mode. By leaving this pin open you have disabled autonomous mode. 

    If you are using I2C to control the device in "AUTO" mode (different from autonomous mode). You will not see the gate voltage until you pass a successful detection cycle. Therefore, you need to connect a valid PD to the port and pass detection, before you will see any gate voltage which controls the external FET. 

    Regards,

    Brandon

  • Hi Beader,

    Thank you for your support.

    We are using autonomous mode, not I2C(disconnected from master) and also Pin 52 reworked and connected to 62K to GND.

    May I know default working state of Pins(OSS, RESET & INT) externally high or Low ?

    And also I am requesting kindly provide wiring diagram between PSE & PD to verify correct PIN to PIN connection between two(PSE & PD).

  • Hi Prabhu,

    OSS is your fast shutdown active high and should be pulled low by default, RESET is active low and by default should be pulled high, INT is your interupt which is active low and default should be high with an external pullup resistor.

    You can reference on of our PD evms for the diagram between PSE & PD. I would recommend taking a look at TPS23730EVM-093.

    Regards,

    Brandon