Tool/software:
Hi Ti Experts,
we want to use the bq27Z746 in a 1S1P application.
I would like to know what the output voltage at the CHG and DSG Pin is.
In the datasheet I found following:
Does this mean if the battery is charged to 4V, I will get at the CHG Pin 8V with respect to VSS?
And the Gate Source Voltage of the CHG FET will be 4V?
When the battery is charged to 3V, the Gate Source Voltage will be 3V, right?
Thanks for helping us.
Regards, Klaus
Hi Diego,
thanks for your answer.
What is the voltage level of the CHG Pin when the Chg-FET should be in off state?
VDD = 4V ->
VchgOFF = VCHG - VSS = 8V - 0V = 8V
I do not understand the euqation. I think the voltage should be 4V or 0V.
Thanks for helping us.
Regards, Klaus.
Hello Adrian,
thanks for your answer.
1st Question:
Please look at following picture. This means if the CHG Pin has +0,2V at the battery voltage is 4V the Gate-Source Voltage of the CHG FET is -3,8V. Is this right?
2nd Question:
How dose the euqation from the datasheet works?
VDD = 4V ->
VchgOFF = VCHG - VSS = 8V - 0V = 8V
Thanks for helping us.
Regards, Klaus
