LM22680: can I connect the 5V coming from the USB to the output of the of the LM22680

Part Number: LM22680

Tool/software:

I am currently designing a project that has 2 voltages input to the design. It can operate at either 12Vdc or 5V from USB. The power supply using LM22680MR-ADJ to give me a +5V output.

My question is, can I connect the 5V coming from the USB to the output of the of the LM22680. I have a circuit to disconnect the USB when I have 12v connected. 

  • Hello

    Can you show me a sketch of your circuit around the LM22680.

    That will help me to better answer your question.

    Thanks

  • This is what I am referring to. LM22680 will be off while there is power to USB connector.

  • Hello

    It depends, if the input voltage to the regulator will be present when the 5V "back-feed" is applied, then it should be OK.

    Usually it is not a good idea to allow voltage on the output of a regulator when the input is zero volts (or even floating in some cases).  There is a diode between the drain(VIN) and source(SW) of the power MOSFET inside the converter.  With a voltage on Vout, and the input held at zero volts, there will be a path from Vout to Vin through the inductor and this diode.  Even if the input is floating, a current will flow and try to charge the input caps, possibly to a high voltage due to resonance with the caps and the inductor.  This phenomenon has been seen in the past under some conditions.  Allowing current to flow through this diode can cause a parasitic to turn on or even damage the diode.  Since it is not a "true" diode but a parasitic formed when the MOSFET is constructed on the die, it is not designed to take current for more than a few 10s-100s nsec.  A blocking diode in series with the load is the best way to prevent any issues from this cause, if VIN is not present during your "back-feed" operation.  TI also has dedicated "diode-OR" controllers that are designed for this type of application.  Please also see app note SLYT689 and SLVAE57 for more information.

    Thanks

  • Hello

    I will close this post due to inactivity.

    Thanks