Tool/software:
BQ34Z100-G1 has a pin called VEN, this is its definition:
VEN (O): Active High Voltage Translation Enable. This signal is optionally used to switch the input voltage divider on/off to reduce the power consumption (typ 45 µA) of the divider network. If not used, then this pin can be left floating or tied to Vss.
According to this forum :
This VEN pin switches high to read the stack voltage then it goes low for power consumption saving.
Also the BQ34Z100-G1 has another pin named REG25, and the following is its definition:
REG25 (P): 2.5-V Output voltage of the internal integrated LDO. Decouple with 1-µF ceramic capacitor to Vss.
According the datasheet of the BQ34Z100EVM, it clearly shows that there is a connection between REG25 and VEN through a "momentary" switch.
According to the datasheet of the BQ34Z100-G1, it states the following:
"Single LED mode—Upon detecting an A/D value representing 2.5 V on the VEN pin, Single LED mode will toggle the LED as duty cycle on within a period of 1 s where each 1% of RSOC is a 7.8125-ms high time. So, for example, 10% RSOC or SOH will have the LED on for 78.1 ms and off for 921.9 ms. 90% RSOC or SOH will have the LED on for 703.125 ms and off for 296.875 ms. Any value > 90% will display as 90%."
So whenever VEN detects a 2.5V it starts blinking the LED.
Can someone please explain to me the relation between VEN and REG25, how things work ? If the switch was pressed knowing that it is a momentary one, VEN which is an output pin would detect a 2.5 V? then shouldn't the gates also detect such voltage ? what happens with the voltage divider ? The LED would blink for how much time, knowing that my system is in single mode then when the LED blinks it reflects what ?
Appreciate your help in advance.
