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TPS6522005-EP: Regarding the efficiency:

Maharajan P
Intellectual 255 points
Part Number: TPS6522005-EP

Tool/software:

Dear Team, 

i am using the above mentioned part as a power management IC in my design. I am configuring the outputs as follows

  TPS6522005-EP TPS6522005-EP TPS6522005-EP TPS6522005-EP TPS6522005-EP TPS6522005-EP TPS6522005-EP
PMIC BUCK and LDOs PMIC Buck 1 PMIC Buck 2 Regulator PMIC Buck Regulator 3 LDO1 LDO2 LDO3 LDO4
Current (A) 3.5 2 2 0.4 0.4 0.3 0.4
Output Voltage (V) 0.9 0.85 3.3 3.3 1.2 1.2 1.2
Input Voltage (V) 5 5 5 5 5 5 5
Efficiency              

But in the datasheet efficiency is only given for 1v8 output voltage.

Please provide me with the efficency filled table and Graphs or any form of source to show where we can determine that particular efficiency.

Please respond ASAP.

Thanks and regards, 
Maharajan P

  • 0
    TI__Expert 6245 points

    Hi Maharajan,

    We have collected Efficiency data at discrete points, please see the attached.

  • 0 in reply to Sathish Vallamkonda
    Intellectual 255 points

    Hi Sathish, 

    Can you please Provide me a clarity Since I cant Understand the Attached Image.

    If its like you share Individual graph for every buck and LDO with respect to the the Input and output requirement that I have Attached in the above table or 
    By filling the efficiency columns of the Above mentioned Table Sharing it to me , It would be More Helpfull

    Thanks and Regards,
    Maharajan P

  • 0 in reply to Maharajan P
    Intellectual 255 points

    Hi Sathish, 

    sorry for the confusoin earlier 
    Please refere the corrected Table Attached Below

    TPS6522005-EP TPS6522005-EP TPS6522005-EP TPS6522005-EP TPS6522005-EP TPS6522005-EP TPS6522005-EP
    PMIC BUCK and LDOs PMIC Buck 1 PMIC Buck 2 Regulator PMIC Buck Regulator 3 LDO1 LDO2 LDO3 LDO4
    Current (A) 3.5 2 2 0.4 0.4 0.3 0.3
    Output Voltage (V) 0.9 0.85 3.3 3.3 1.2 1.2 1.2
    Input Voltage (V) 5 5 5 5 5 5 5
    Efficiency              

    LDO4 current was mentioned as 0.4A earlier now it is corrected to 0.3A

    Thanks and regards, 
    Maharajan P

  • 0 in reply to Maharajan P
    TI__Expert 6245 points

    Hi Maharajan,

    For LDOs there won't be any Efficiency curve, just take the drop across the passFET based on the RDSON value.

    Sathish

  • 0 in reply to Sathish Vallamkonda
    Intellectual 255 points

    Hi Sathish, 

    Thank you for the response, 

    For Buck 1 , 2, 3 can you provide separate Graphs and the efficiency Percentage based on the values i have mentioned earlier in the tabular column.

    Thanks and Regards, 
    Maharajan P

  • 0 in reply to Maharajan P
    TI__Expert 6245 points

    Hi Maharajan,

    No, we didn't collect the efficiency at those voltages for Bucks.

    Sathish

  • 0 in reply to Sathish Vallamkonda
    Intellectual 255 points

    Hi Sathish, 

    Can You please suggest me any alternate approach for calculating Efficiency for the Above mentioned BUCK regulators, 

    Thanks and regards, 
    Maharajan P

  • 0 in reply to Maharajan P
    TI__Expert 6245 points

    Hi Maharajan,

    3.3V would be very close to 3.4V data provided.

    0.85V/0.9V would be in the middle of 0.6V and 1.2V data provided.

    Without knowing the exact input and output currents, i don't think there is any other way to calculate the exact efficiency.

    Sathish

  • 0 in reply to Sathish Vallamkonda
    Intellectual 255 points

    Hi Sathish, 

    Efficiency is required to Calculate Input current. PLease Provide the Highest efficiency possible for the Parameters provided in the Tabular column mentioned above 

     
    In the Above mentioned Graph does those voltages are fixed or we can change, 
    And what does the Load set Label mean In the above provided Graph.

    Can i get to how to do that simulation so that i could try once.

    Thanks and regards, 
    Maharajan P

  • 0 in reply to Maharajan P
    TI__Expert 6245 points

    Hi Maharajan,

    The plot shows the voltages for the data collected. You can not change those values. Load set is the output load current.

    This is not the simulation data. You have to measure the input and output voltage and current at each point to generate the Efficiency plot.

    For 0.9V/0.85V you can assume the peak efficiency at about 85% for Buck1 and couple of points lower for Buck2.

    Sathish

  • 0 in reply to Sathish Vallamkonda
    Intellectual 255 points

    Hi Sathish, 

    TPS6522005-EP TPS6522005-EP TPS6522005-EP TPS6522005-EP
    PMIC BUCK  PMIC Buck 1 PMIC Buck 2  PMIC Buck 3 
    Current (A) 3.5 2 2
    Output Voltage (V) 0.9 0.85 1.8
    Input Voltage (V) 5 5 5
    Efficiency      

    TPS6522005-EP TPS6522005-EP TPS6522005-EP TPS6522005-EP
    PMIC BUCK  PMIC Buck 1 PMIC Buck 2  PMIC Buck 3 
    Current (A) 3.5 2 2
    Output Voltage (V) 0.9 0.85 1.8
    Input Voltage (V) 2.5 2.5 2.5
    Efficiency      

    The above attached two Tables  Contains the INPUT and OUTPUT Voltages of the BUCKs, 

    Can You please plot and share the Efficiency for the above given Details, 
    Or please guide me how to do it, I'll give it a try also, 

    Efficiency is critical to estimate the Input current and the power dissipation.
    Please provide me with the efficiency for the above given details as soon as possible,

    Thanks and regards, 
    Maharajan P

  • 0 in reply to Maharajan P
    TI__Genius 9867 points

    Hi Maharajan, 

    Sathish is currently out of office, I can provide support in the meantime.

    I believe I just answered this on your other thread here, 

    but to reiterate, the TPS65219(-Q1) Efficiency and Thermal Estimator Tool can be used to obtain an estimate of efficiency data for your specified parameters. 

    Best Regards,
    Sarah