Tool/software:
Hello Expert,
I am using LMR38010 for designing Buck converter from 11.5V to 36V to 10.5V output @ 1A .
Switching frequency : 700KHz, Inductor used 47uH.
Max inductor current is around 1.2A. (Delta IL of 0.2A )
From Datasheet.
Low side switch min current is 0.9A and Max current is 1.5A
From above inductor current , Low side switch current starts with negative slope and in our case it will be 0.8A to 1.2A. Since datasheet mentions the Low side switch limit is 0.9A to 1.5A , if in case of lower tolerance (0.9A) how load current of 1A or inductor peak current of 1.2A maintained through low side switch ?
Our understanding is during the positive slope of inductor current High switch of IC will be ON and during negative slope of inductor current low side switch of IC will be ON. So when inductor current is above 0.9A (worst case tolerance ) then IC will go to protection ?
Is there is any misunderstanding from our side ?
Thanks
regards
Vasu