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TLV62569: R1 + R2 not present - what happens

Part Number: TLV62569

Tool/software:

Hello,

I am working on a device where the main semiconductor manufacturer has stated that the TLV part should not have R1 and R2 (or C3) loaded at all, meaning the FB is floating.

The input voltage is 3.3V

What would result if this is the case, and what would the output voltage be?

I am trying to find out why this was changed, but I cannot spot anything in the datasheet which would support this layout.

Previously we had 499K for both R1 and R2, and 22pF for C3. But they want all these as DNM/DNP components, making the FB open.

Please advise what would result

TLV62569DBVR

Thanks

  • Actually, FB is not open, its connected to the Espressif controller.

    This is for a ESP32-P4 design, and this pin goes back to the FB_DCDC pin (Pin 78) on the Espressif ESP32-P4 SoC.

    I assume the SoC is doing the feedback to the TLV part. 

    Curious stuff.

    Reference, top of Page 2 is the TLV in question:

    dl.espressif.com/.../esp32-p4-function-ev-board-schematics.pdf

  • Hi J B, 

    Thanks for your question. I will get back to you as soon as possible.

    Best Regards

  • Hi J B,

    For the first question, if you keep the FB pin floating, this would make the device out of control as you are not closing the control loop of the device. Depending on the float voltage, you would either see a 0V or unstable output voltage that could turn off the device.

    If FB is not open and connected to Espressif controller then the question is how would the controller knows about the load transients and convey the information to the device quickly? 

    We would always recommend our datasheet specified configuration for the correct operation of device. Slight smile

    Best Regards

    Zakir