BQ28Z620: Abnormal reading of current, reading data is 0

Tool/software:

At present, we have applied your company's BQ28Z620 chip to our actual project, working together with the BQ25798 chip. However, we have discovered an issue where our board should have a current of 70-80mA when turned on, but the data we read back with bq28z620 is 0, and our EE colleague's data read back on BQStudio is 80mA

After a period of time, the current is shown in the figure
May I ask what possible reasons may have caused it
The relevant code and data read by the logic analyzer are as follows

#define  BQ28Z620_CMD__CURRENT  0x0C

static int read_reg(const msdk_device_t *dev, uint8_t reg, uint8_t *value, uint8_t size)
{
    int ret = MSDK_STATUS__ERROR;

    const bq28z620_cfg_t *const dev_config = (const bq28z620_cfg_t *const)dev->config;

    ret = msdk_i2c_read_reg(dev_config->i2c_dev, dev_config->i2c_addr, reg, value, size);

    return ret;
}

static int read_current(const msdk_device_t *dev, int16_t *milli_ampere)
{
    uint8_t current_data[2] = {0};
    int res = MSDK_STATUS__ERROR;

    res = read_reg(dev, BQ28Z620_CMD__CURRENT, current_data, sizeof(current_data));

    if (MSDK_STATUS__OK == res) {
        uint16_t raw_value = (current_data[0] << 8) | current_data[1]; 
        
        if(!(raw_value & 0x8000)) {
            *milli_ampere = (int16_t)raw_value;  
        } else {
            *milli_ampere = -(int16_t)(raw_value & 0x7FFF); 
        }
    }

    return res;
}
msdk_status_t bq28z620_property_get(const msdk_device_t *dev,
    msdk_fuel_gauge_property_t prop,
    msdk_fuel_gauge_propval_t *val)
{
    MSDK_ASSERT(dev != NULL);
    MSDK_LOG_DBG("bq28z620_property_get: dev 0x%08x, prop %d", dev, prop);
    int res = MSDK_STATUS__ERROR;

    switch(prop) {

    case MSDK_FUEL_GAUGE_PROP_CURRENT: {
            int16_t mA = 0;
            res =read_current(dev, &mA);
            val->current = (int32_t)mA;
        }
        break;
    	
    default:
        res = MSDK_STATUS__NOT_SUPPORTED;
        break;
    }

    return res;
}

Best Regards!

Iris