Tool/software:
Hello Team,
I just want to make sure.
For Stand-alone operation in Auto-retry mode with supply volatge of 12V and current limit of 1 A, if I am considering maximum possible rating,
The R(CL) for current limit of 1 A would be, VCL(TH) x K (CL) / I(out) = 0.8 x 2500 / 1 = 2000 Ohm
The power rating for the R(CL) would be, VCL(max)^2 / R(CL) = 7^2/2000 = 0.025 W
The power rating for the R(Delay) would be, Vin^2 / R(CL) = 12^2/100k = 0.00144W
Thanks in advance.
