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Original question:

UCC28910: New Transformer design & component values

UCC28910: UCC28910 design for 9.6W (24V 0.4A) output (AC/DC).

WF KWOK
Prodigy 70 points
Part Number: UCC28910
Other Parts Discussed in Thread: UCC28911, UCC28881, UCC28750

Tool/software:

We are going to use UCC28910 to design a buck converter with 24V output and 0.4A.
There is an application note for UCC28910 operation scheme in Buck mode for Output voltage: 20 V, Output current: 100 mA.

However, the power output is not sufficient for us and we would have the 9.6W (24V 0.4A) output.
So can the circuit output such a power rating? And how can we change the circuit?
What components and values do we need to change from the design in the application note?

Furthermore, if the UCC28910 cannot meet our power output requirement, how about UCC28911? or any other IC suggestion?
If UCC28911 can meet our power output requirement, can we apply the same design circuit in UCC28910 application note?
And what components and values do we need to change from the design in the application note for UCC28911?


Thank you very much.

https://www.ti.com/lit/an/snva750/snva750.pdf?ts=1756865057728

UCC28910: up to 7.5W
UCC28911: up to 10W

  • 0
    TI__Guru* 86266 points

    Hello,

     

    You can not use the UCC28910 or a UCC28911 converter in a buck design for current more than a 150 ma.  The below graph shows the maximum current the UCC28910/11 can be design for in a buck converter.

     

    The only other device that we have for with an internal FET for low power is the UCC28881 that can be designed in a buck application can only handle 225 mA of current.

     

    I would recommend using the UCC28750 in high side buck instead with an external FET.  The following link will bring you to reference design that you should be able to modify for your application.

    https://www.ti.com/tool/PMP31338

     

    If you have questions about how to use the UCC28750 in this application please repost in the e2e with UCC28750 in the thread title.  This is so the appropriate applications engineer can help you.

     

    Regards,