Tool/software:
Dear TI members,
I wanna use 1963A-KTTR model in order to convert 8.4 V to 3.3V , I know it is not a good idea in terms of efficiency, but I want the lowest noise possibly and I dont want any external inductor like in the buck convertor case.
I will drop 8.4V to 3.3V but the output current will be really small , like around maximum of 200mA.
Can I use this one? I wanted to be sure about, it will not pop.
Thanks in advance
Hi Berke,
Thank you for asking us!
This device (like most of our portfolio) is equipped with a thermal shutdown circuit to protect the device from overheating, so it will only temporarily shut down if it overheats and not suffer damage. Though if the conditions allow it to overheat again once it cools down and turns back on, it will repeat the cycle.
That (8.4V -> 3.3V @ 0.2A) is about 1.02W of power dissipation, or a 33.6'C temperature rise from ambient with a KTT package typical RθJA value of 32.9'C/W (per below datasheet table).
Note that the thermal metrics are calculated in simulation for a JEDEC standard board and will vary depending on the thermal properties of your board design and layout. I can provide more information on those conditions if you'd like.
That means that your device should be capable of remaining within the recommended operating temperature range (below 125'C) (where the electrical characteristics table applies) up to an ambient temperature of 91.4'C.
You can use this one.
Best,
Gregory Thompson
