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LM5117 UVLO

I’m having trouble understanding the formula to choose the UVLO resistors. The resistor between the UVLO pin and ground Ruv1 is typically going to be a much smaller value than the resistor from the pin to the input Ruv2. So if I’m switching a 20 uA source into this circuit for hysteresis, I would think the resistor to ground would have much more effect on the voltage shift caused by the current source than the resistor to the input. Actually, I would think the resistance of the two resistors in parallel would define the amount of voltage shift from switching in the 20 uA current source, but this resistance is close to the resistor to ground as this resistor is much smaller.

 

Using the quick start spreadsheet when I want the UVLO at 9.2 Volts and 100mV hysteresis, I get 790Ω and 5K which agrees with the data sheet formula, but it doesn’t make sense to me. 20uA and 790Ω = 15.8 mV, not 100 mV?

  • Hi Martin

    dVin * Ruv1 /(Ruv1+Ruv2) = Ruv1*Ruv2/(Ruv1+Ruv2) * 20uA, where dVin is the required hysteresis voltage and 20uA is the hysteresis current.

    Dividing both side of the equation by Ruv1 /(Ruv1+Ruv2) will obtain  dVin =Ruv2 * 20uA .

    Please don't forget that Ruv2 is not always greater than Ruv1.

    Regards,

    Eric