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TL3844 based SMPS design

Other Parts Discussed in Thread: TL3844

Hi, I have designed a SMPS with the following input and output specs and the design is based on TL3844. Kindly let me know if the design is OK.

Input = 20V to 150VDC

Output = 5V at 3 Amps

Operating freq = 40KHz, assumed efficiency = 75%, Max Duty cycle = 0.45(discontinuous mode)

I get a turns ratio of 3, Primary inductance of 315 microHenry,

Primary turns of 72 and secondary turns of 24 (for 5V)

The transformer core selected is EE2005 and a 300V MOSFET is selected.   KIndly let me know if the design is OK

TL3844 has max duty cycle of 50% and start up threshold of  16V

Regards

Atul Bhakay

  • Atul,

    I used the free power stage designer tool from TI
    http://www.ti.com/tool/powerstage-designer

    It suggested a 59uH primary and 3:1 turns ratio using a flyback design..

  • Hi,

    How to calculate the value of the start-up resistor for TL3844 or similar PWM controllers ?

    Regards

    Atul Bhakay

  • Hi,

    The max start-up current for TL3844 is 1mA. So for min input voltage of 20VDC, if the start-up resistor is 20K, then I get the start-up current of 1mA. But at high line of 150V, with 20K as start-up resistor, I get 7.5mA. Is this OK ?

    Regards

    Atul Bhakay

     

  • 0841.TL3844_3 output_EE2005_Transformer.doc

     

    Hi, Kindly verify theattached  transformer details of this TL3844 based SMPS

    Regards

    Atul Bhakay

  • Atul,

    The TL3844 "start up current" is the current that the TL3844 draws before start up. The TL3844 has to start up before 17.5V.
    Therfore at 20V input and a 17.5V at VCC with a current of 1mA requires a resistor less than 2.5k = (20V-17.5)/1mA
    With 150V, the input current will be 53mA = (150V-17.5V)/2.5k. This is 7 Watts! = 53mA^2*2.5k.
    There needs to be a capacitor on the TL3844 VCC pin that can supply power to the TL3844 long enough the start up the secondary power source to the TL3844 before the VCC drops below the under voltage dropout threshold.

  • Hi Ron,

    Thanks for yr reply.

    At the beginning, when Vcc is 'zero' volts and the Vcc capacitor is being charged thro the start-up resistor, then with a input of 20V and a max start-up current of 1mA, should not the value of start-up resistor be 20V / 1mA = 20K ohms ?

    Also, since the minimu operating threshold voltage , after start-up is typically 10V for TL3844, the bias winding ahs to be designed for 10V - correct ?

    These are the 2 queries I have.

    I am waiting for a reply on how to select the resistors connected from VFB pin when an opto-coupler is used in the TL3844 SMPS

    Regards

    Atul bhakay

  • Atul,

    My knowledge in transformer construction is not sufficient to answer the transformer spec question. You can contact the transformer manufacturer or post a new thread.

     

     

  • Atul Bhakay said:

    At the beginning, when Vcc is 'zero' volts and the Vcc capacitor is being charged thro the start-up resistor, then with a input of 20V and a max start-up current of 1mA, should not the value of start-up resistor be 20V / 1mA = 20K ohms ?

    Also, since the minimum operating threshold voltage , after start-up is typically 10V for TL3844, the bias winding has to be designed for 10V - correct ?

    The data sheet parameters describe the TL3844 operation, not the application operation. They don't need to match, they need to be satified. 
    The current in to the TL3844 will be a maximum of 1mA per data sheet. This means less than 1mA of the resistor's current flows into TL3844 and the rest charges the capacitor. There must still be at least 1mA of resistor current flow even if the capacitor voltage is 17.5V. 

    At 10V VCC half of the TL3844 population will be shutdown. VCC must remain greater than 11.5V to ensure all TL3844 devices remain on.

     

  • Hi Ron,

    Thanks for the suggestion on calculating the start-up resistor. With the suggested value of 2.5K, I was able to get the SMPS 'working' and delivering the reqd power, too.

    However, I noticed that at 20VDC input the VCC pin voltage is around 10.8V and at 120VDC input, the VCC pin voltage is 12.2 V. Why this variation , hwen I have a VCC winding ?

    Regards

    Atul Bhakay

     

  • Atul,

    Check the voltage waveform on anode of the diode for the VCC winding rectifier. If you have the correct winding polarity, then the positive peaks should be about the same. What is that peak voltage?

  • Hi Ron,

    Thanks for this important tip. Yes, I will check the anode voltage waveform of the VCC winding diode. However, prima facie, will the VCC voltage change as Vin increases ?

    Regards

    Atul Bhakay

  • Hello Atul,

    in flyback please consider ever: the wave form at secondaries is the opposite of the primary wave form; that's to say: with a DC about 0.3 at primary winding (Vgate about: __--__--__), you will get positive pulses -measured on diode anodes, against GND- with DC=0.7 (approx.: ----_----_). The positive value of them will be your VCC output values, while the negative ones could be very high if you have a high Vin value together with a low n.

    n=3 is quite ideal for most applications.

    Alejandro Sincich