Hello: I'm trying to figure out the cheapest and lowest-component-count way of working with the bq25504 on a system where the load voltage must be <3.6V, but the battery should be 4.2V. The load voltage does not need to be especially stable, it just needs to be 2V < Vload < 3.6V. For the record, 1.5uA < Iload < 20mA.
I would love to hear if anyone has experimented with this. I'm going to post my hypotheses below, and if you have comments, please post!
I suspect one way to do it is just to put a diode between VSTOR and the external load, such that there is a forward drop enough to bring voltage below 3.6V. In this case, I am *hoping* that at loads below the diode Vf, 4.2V isn't going to hurt any of the components.
It seems that bq25504 switches between VSTOR and VBAT as the source of Vdd (as it needs to charge each of these), so putting a diode between VSTOR and CSTOR would not seem to work. This would be preferable to the first solution if it did work, since it would provide better limiting on the voltage of CSTOR. It may be possible to use two diodes in reverse directions, though.
In any case, if TI is listening, a lot of batteries like 4.2V charge voltages, and an increasing number of ultra-low-voltage digital parts do not like Vdd higher than 3.6V. If you make an update to the bq25504 (maybe bq25504b or whatnot), it would be much appreciated if Vstor could be set less than Vbat. It seems to me that this would be a relatively simple change to the boost converter logic.