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LM3410 - Need help calculating Capacitor and Inductor values

Other Parts Discussed in Thread: LM3410

Hi there,

I recently got a LM3410Y in a SOT23-5 package to power an LED back-light of a TFT LCD screen. The screen requires 19.2V @ 40mA for 12 LEDs. There no mention of forward voltage for each LED in the datasheet.

Here is a link to the LM3410Y datasheet:

http://www.ti.com/product/lm3410

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Here is a link to the LED TFT LCD screen:

http://www.newhavendisplay.com/nhd43480272efatxlt-p-5571.html

My Vin is going to be 3.3V @ 100mA and my Vout can be between 19.2 to 22V, so I am going with 20V @ 40mA.

Vin = 3.3V @ 100mA

Vout= 20V @ 40mA

Looking at the datasheet I calculated that the series resistance required is Rset= VFBmax/ ILED => 202mV / 40mA => 5.05 ohms.

To get the inductor value it is D= (Vout-Vin)/Vout => (20V-3.3V) / 20V =>.835

Ts => 1 / fsw => 1 / 525KHz => 1.9048 x 10^-6 seconds or 1.09048us

(525KHz used since this is the LM3410Y and not X)

L = (Vin/ (2*dela IL)) x DTs

delta IL = ??? it is unclear how to obtain this from the graphs and equations shown.

In sum, I am not sure how to calculate the inductor and capacitance values required as this part is a bit confusing to me. If anyone can assist me with trying to figure out how to properly calculate the required inductance and capacitance values it would be much appreciated. Thank you.