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About continuous & discontinuous conduction mode of LM2832YMY.

Satoshi
Guru 19655 points
Other Parts Discussed in Thread: LM2832

Although examined by attached specification, low output current should also teach how to make it operate by continuous conduction mode.
(Is it a method except enlarging an inductor?)
 
Moreover, how much does ripple voltage become?

Thank you for your consideration.

  • 0
    Guru 19655 points

    Is it difficult to find such a cause?

    If there is information which becomes a key, please let me know.

  • 0 in reply to Satoshi
    TI__Guru**** 191445 points

    LM2832 is a non-synchronous converter.  It will operate in CCM only if the load current is greater than 1/2 the peak to peak inductor ripple current.  For example in case 1, you would need to limit ripple current to 16mA/2 = 8 mA.  That would require an inductor value of 284 uH.  LM2832 is internally compensated.  It is usually designed for higher output currents.  You may have stability issues using an inductor 60 times larger than 4.7 uH.  Why do you need to operate in CCM?

  • 0 in reply to JohnTucker
    TI__Genius 11085 points

    Is there any special reason why CCM operation at 16mA is preferred?

    If CCM operation is a must, a synchronous buck converter with FPWM mode at light load should be a better option.

    Yang