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TPS61042 Switch Rds(on)

Other Parts Discussed in Thread: TPS61042

Hi All,

I notice that the Rds(on) of the switch for the TPS61042 does not seem to come into the equations for calculating minimum load current (other than to effect the efficiency). It would seem to me that this would have a significant effect at low voltages, for example an Rds(on) of 2 ohms would introduce a voltage drop of 1V at 500mA so that the voltage across the inductor when current is ramping up would be less, and Rds(on) may well be higher than the quoted 2 ohms at low voltage.

My question is this: Do the conditions that cause Rds(on) to increase towards its maximum also cause the peak current value to increase towards its maximum? Rds(on) increasing would effectively slow the switching frequency, and hence tend to reduce the max power that can be transferred into the output, but if Ipeak increased proportionally then the energy transferred per cycle would increase to compensate.

In other words, can I neglect the Rds(on) value and simply use the Ipeak(min) value of 400mA in my calculations and an efficency of 70% when calculating the load current at minimum input voltage?

Thanks!

Mark.

  • If you are talking about the FET that is used to implement dimming, between LED and RS pins, then its effect will be captured by increasing the value of your expected Vout in the equations.  It is part of the load and not the boost power stage so it will cause an increase in the required output voltage and therefore output power demanded.  The effective duty cycle increases.

  • No,l'm not using the LED FET. I'm trying to figure out whether the switch FET's on resistance would need to be taken into account. I made an error in the original post by quoting 2 Ohms, this should really read 0.6 Ohms. If you look at the spec for the TPS61042 you'll see 0.6 Ohms as the max at Vi = 3.6V with a typical of 0.3 Ohms. The typical figure matches the graph (Figure 8) that shows how the typical figure increases to 0.550 Ohms at 1.8V. Assuming the max figure scales by the same amount, this yields approximately 1 Ohm for the switch worst case. So 500mA at 1 Ohm is 0.5V, i.e. 27% of 1.8V, so it will have a significant impact on switching speed, which effects max power deliverable at low voltages. The question is whether the conditions that cause Rds(on) for the switch to increase also cause the switch current to increase (this can be between 0.4A and 0.6A). If that were the case then the energy transferred per cycle would increase, this would negate the lower switching speed effect and the max power transferrable at low voltages wouln't be affected by the Rds(on) of the switch.

    So, can I neglect the Rds(on) of the switch when working out the minimum deliverable power at low voltages?

  • Then, yes, you are correct in that the datasheet equations ignore the effect of the power FET's Rdson to simplify them.  Your estimates for the max Rdson seem reasonable.  So, for a good approximation you could simply replace Vin in the fsw(load) equation with Vin - Ilim*Rdson, for example, at Vin=1.8v and with Rdson=1ohm, Vin-Ilim(max)*Rdson(max) = 1.8V-0.6A*1ohm = 1.2V worst case. 

  • OK, thanks. However it doesn't really answer whether the peak current limit I(LIM) actually rises under the same conditions as Rds(on) increases. Obviously it won't exceed 0.6A (plus a bit for the 100ns delay). I guess we would need to know the relationship between these internal to the chip to know the answer.

    As an aside, are there any Spice models (or other simulation models) available for the TPS61042? This would be really handy for at least estimating whether a circuit would work.

    Mark. 

  • Actually as a note to the designers of the chip there is another feature I would like to see that would be handy. Currently the CTRL pin has a Vih abd Vil of 1.3V and 0.3V. If this threshold voltage were accurately specified (using the bandgap reference), and possibly with a little bit of defined hysteresis,  then we could easily add a low voltage lock-out by simply using a resistor divider on the CTRL line.

    Mark.

  • From the block diagram, the current limit circuit measures the voltage across an internal resistor (not shown) to ground.  If that fixed resistance only increases slightly with temperature and the current limit comparator is simply a comparator, then the current limit value trip point  should remain fixed and possibly get lower with temperature. 

  • The TPS61042 current limit circuitry is not linked to the power FET's Rdson.

  • OK, thank you Michael and Jeff.

    I'm curious as to why there is such a variation in I(LIM), which can be 0.4A to 0.6A. I assume it's because of the very low voltage drop across the sense resistor and that this resistor value can't be tightly controlled in absolute terms. Anyway I think my question has now been answered, thanks.

    Mark.

     

  • You are correct in that the variation in the resistor value is the primary reason for the variation in ILIM.