Hello,
I have a lot of questions about the LM3406HV. I want to drive a power LED (40W) and I have following requirements:
Uin = 42..48V
Uout = 36V ; 1A
1:
I want to dim the Power LED with the normal DIM Input, but I'm not sure, if it is possible with this conditions.
I cant estimate, if I get a wide area of values of duty cycles.
I have found in the user guide http://www.ti.com/lit/ug/snva407b/snva407b.pdf on page 3 ,
that the duty cycle dependent on the switching times. The problem is the minimal duty cycle:
D_min = (t_D + t_on_min ) / T
My frequency f is between 340kHz and 390kHz.
And I know t_on_min = 230ns.
Do I have any chance to estimate t_D ?
My LC filter is L=22uH, C=1uF.
2:
In the user guide AN-1993 LM3406HV Evaluation Board with 2 Wire
Dimming on page 4 http://www.ti.com/lit/ug/snva407b/snva407b.pdf stands:
"A voltage of up to 30V must be applied to the DPWR pin to operate U5"
But, is 30V not to high for the mosfet Si4464DY (http://www.vishay.com/docs/72051/72051.pdf) ?
This have a U_GS from +-20V ?
Could you explain it, please?
3:
The n and p-mosfets in U5 http://www.fairchildsemi.com/ds/FD/FDC6333C.pdf get the switching signal in the same time. Is there any problem in the junction?
I mean if one mosfet is still on and the other is already on.
4:
If U_IN swings, for example 42V to 48V. The LM3406HV change the frequency and the duty cycle. What is the advantage of changing both, and not only the duty cycle?
5:
In the datasheet http://www.ti.com/lit/ds/symlink/lm3406.pdf on page 19, the z-diode is between the anode of LEDs and the resistances, to protect the cs input.
Why can't I connect the anode of z-diode with ground?
Thank you in advance for reading and answering my questions.