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BQ24251 stops switching if the battery is remove and then insert

Other Parts Discussed in Thread: BQ24251

Hi,

When battery is removed and then re-insertion from the battery voltage is NOT below 0.4V,

the BQ24251 does not start switching.

Re-insert from below 0.4V will start switching.

Why this differnce occurs?

  • Hello, Keiichi,

    Can you describe how did you remove and re-insert the battery in detail?

    - What was the battery voltage before you remove it and what was the battery voltage when you re-insert?

    - What was the voltage that you saw when the part start switching? Did you monitor the SW pin to tell if it is switching?

    Thanks,

    Wenjia

  • Wenjia,

    Thanks for your reply.

    We can duplicate battery voltage at 4.3, 4.0 and 3.6V, but it seems that it does not depends on 

    original battery voltage.

    I attached waveform as below

    Ch1 is VBAT pin and Ch2 is VOUT voltage beyond inductor.

    We once remove battery and then wait,  and re-insert at following voltages.

    Case 1) NG case : Re-insert battery at VBAT=0.4V

    Case 2) Good Case :  Re-insert battery at VBAT=0.8V

    Case 3) Good Case : Re-insert battery at VBAT=0V

  • Hi, Keiichi,

    I'm still trying to understand the set up here. If you don't mind, please help to provide the below information also.

    - When you remove the battery, what is connected to the BAT pin of the device? I guess I'm try to know where is the 0.4V and 0.8V from.

    - Do you have a power at VIN? Looks like your OUT pin stays at 2V with or without a battery, which is also not what I expected.

    - For the above waveforms, did you use a real battery or a simulator to mimic the 4.3V battery?

    Thanks,

    Wenjia

  • Hi, Wenjia

    There are no connection other than capatitor(10uF) on VBAT.

    Also VIN have no power resources, only have 22uF+22uF+0.1uF capacitors. I guess these capacitors let VIN 2V.

    We uses real battery for remove/insertion which have 4.3V, 4.0V and 3.6V (As I wrote before)

  • Hello, Keiichi,

    I duplicated your condition on bench today, and please see the waveform attached. For a 3.6V battery, I tried insert it with VBAT = 0V, 0.4V and 0.8V just like what you did, and in all cases the system is powered on normally. If you can send me your schematic, I can try to further check the issue for you.

    Also, I hope you can help me understand how the VBAT pin can have different voltages without anything connecting to it (0V, 0.4V, 0.8V). In my experiment, I used a separate power supply to mimic your condition unless the VBAT will stay 0V. The 10uF cap is a lot bigger than recommended on data sheet, can you try use a 1uF cap instead?

    VBAT=0V

    VBAT = 0.4V

    VBAT = 0.8V

    Thanks,

    Wenjia

  • Wenjia,

    At first, Thank you for duplication trials.

    As for schematic, It will be customer information, so would you tell me appropriate mailing address?

    I would like to send you directory.

  • Please send it to wenjia.liu@ti.com.

    Thanks,

    Wenjia

  • Wenjia,

     Thanks for your support.

     I sent you a schematic directory via e-mail.

    I got additional information from customer.

    1) They can only duplicate at 1/20 by remove/insertion batteries. Possibility is low.

    2) They tried to duplicate by using DC power supply, but they can not.