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TPS63060 – About Quiescent current

Hide
Guru 21045 points

Hi,

 

My customer would like to calculate a dissipation power(Pd) at Iout=0mA(no load).

Therefore, we would like to ask about quiescent current (Iq_out).

 

--------------

[Q1]

Could you please send us it, if you have a graph such as Figure27?

So, I would like to ask whether the Iq_out is changed by the output condition.

 

 

---------------

 

[Q2]

My customer will calculate as follows.

Therefore, we would like to ask about Iq_out.

Please let me know if we are mistaken.

 

<Pd at Iout=0mA(no load) calculating formula>

Pd = (Vin*Iq_IN) + (Vout* Iq_OUT)+ (VEN * EN,PS/SYNC input current)

--------------

 

I’d greatly appreciate your verification.

 

Regards,

Kanemaru

 

  • 0
    Guru 21045 points

    Hi,

     

    I have one more question.

     

    [Q3]

    I believe that the test condition of the quiescent current (Iq_IN) which is mentioned in datasheet is “PS/SYNC=GND”.

    So, if the test condition is "PS/SYNC=VIN(7.0V)", I guessed that the Iq_IN does increase from the value which is mentioned in datasheet.

    Is my understanding correct?

     

    We evaluated the TPS63060EVM and obtained a result as follows.

    ・Iq_IN≒70uA at Iout=0mA , PS/SYNC=GND

    ・Iq_IN≒13mA at Iout=0mA , PS/SYNC=7.0V

     

    <Evaluated conditions>

    Vin=7.0V

    EN=7.0V

    PS/SYNC=7.0V or GND

    Vout= 5.0V

    Iout= 0mA (no load)

     

    I’m looking forward to hearing from you.

     

    Regards,

    Kanemaru

  • 0 in reply to Hide
    TI__Expert 7110 points

    Hi Kanemaru-san,

    let me briefly summarize the answers:

    Q1:
    We specify the Iq at VOUT just for VOUT = 5V

    Q2:
    With this approach, you can basically calculate the dissipation for idle condition

    Q3:
    For PS/SYNC = high, the device is forced in PWM and has more inrush current for idle condtion

    Regards,

    Florian

  • 0 in reply to Florian Feckl
    Guru 21045 points

    Hi Florian-san,

     

    Thank you for the information.

    I understood. thank you very much.

     

    Regards,

    Kanemaru