Dear Tiers.
BQ24075's Vout(Reg) is 5.5V in below condition.
Vin>Vout+Vdo(300mV).
This means when Vin is 6V, Vout is 5.5V. Is it right?
Another question.
If Vin is 5V, Vout is 5V or 5V-Vdo(300mV)=4.7V?
This thread has been locked.
If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.
You are right that when Vin is above Vout + Vdo, Vout will be regulated to 5.5V.
If Vin is 5V, Vout = Vin - Iout*Ron. The value depends on the real dropout across the FET.
Thanks,
Wenjia