Hi.
A comment in the LM5118 quick start calculator on the cell for Rfb2 (not Rfb1) says the following - "From quick start - Rfb1 is typically chosen to be a vlaue which will allow 1ma or greater divider current for noise immunity. For example, for a 12 volt output choose Rb1 to be 1.2k or smaller."
Should the example of 1.2k actually be 12k? Or is the desired minimum current 10mA? Or is this expecting Rfb2 to make up the rest of the 12k? If so, it seems perhaps more appropriate to calculate Rfb1 on the Feedback reference voltage.
Also, does this help make the output less noisy? More stable?
Thanks.