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TPS92630-Q1 - K(I) "Ratio of I(IOUTx) to reference current"

Other Parts Discussed in Thread: TPS92630-Q1

Hello,
I have a question about TPS92630-Q1.
Page-5 of the data-sheet "SLVSC76B".

Please teach me the MIN-value and the MAX-value of K(I) "Ratio of I(IOUTx) to reference current".
SLVSC76B describes only the TYP-value "100".

The purpose is to calculate the variability of output current accuracy.

Regards,
Daisuke

  • Hi Daisuke-san,

    You may have an older copy of the datasheet. I just checked online and this inforamation is now on page 5:

    Regards,

  • Hello John,
    Thank you for your reply.

    Is there the MIN-value and the MAX-value of K(I)?

    Best regards,
    Daisuke

  • Hi Daisuke,

    K(i) number is only for customers' calculation information only. The accuracy is explained in details in the output current accuracy part on page 5 of the datasheet.
  • Hello Anda,
    Thank you for your reply.

    When I use ΔIo(device) of the table as follows, is it not necessary to consider the variability of K(i)?

    I think I(setting) is calculated by equation-1.

    Does ΔIo(device) include the the variability of K(i)?


    Doesn't ΔIo(device) include the the variability of Vref?


    Doesn't ΔIo(device) include the the variability of R(ref)?


    Best regards,
    Daisuke

  • Hi daisuke,

    The ΔIo(device) doesn't include the variability of K(i) (Actually corresponds with the internal error amplifier  )and Vref. The ΔIo(device) doesn't include the variability of R(ref), actually if you use a 0.1% resistor the output current accuracy will not be influenced too much. 

  • Hello Anda,
    Thank you for your reply.

    If the ΔIo(device) doesn't include the variability of K(i), must we consider the variability of K(i)?
    If so, we need the MIN-value and the MAX-value of K(i).

    Best regards,
    Daisuke

  • Daisuke,

    Sorry for confusing you. It is a typo in my previous answer. Please forgive my mistake.
    The ΔIo(device) includes the variability of K(i) (Actually corresponds with the internal error amplifier )and Vref. But the ΔIo(device) doesn't include the variability of R(ref), actually if you use a 0.1% resistor the output current accuracy will not be influenced too much.