Hi Sir,
My customer currently test CSD19535KTT D2PAK package to replace IRLS4030-7PPbF.
simulation use 6Vgs driver CSD19535KTT, test result ask me CSD19535KTT turn on fast but Qg is not be small,
Base on CSD19535KTT need enough driving current, I suggest UCC27714 ( replace IRS21867S ), can driving CSD19535KTT?
1. Qg= I * Δ T = C * V2, if CV2 is constant, choices sink / source current can determine turn on time, right?
2. We can guarantee test condition as below VGS = 10V, VDS = 50V, ID = 100A can have Qg 75nC ~ 98nC?