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BQ500511: How to detect the removal of RX after having completed the charging

Jacky Wang23
Prodigy 50 points
Part Number: BQ500511
Other Parts Discussed in Thread: BQ50002A

In the datasheet of bq500511 and also bq50002a, there are some descriptions about the detecting RX in the PAD and steps to start-up charging, and the EPT, ending charge, etc.

Though I get to understand the process mentioned above, and other process such as detecting RX, Pings, communication and negotiation about the power transfers,   I still have no clues about how can TX management IC know RX is removed away of PAD after the charging has completed and IC have already entered the Sleep-Mode.

In our application scenarios, we need record the devices'   (in other word, RXs)  charging process, including the time when to put on PAD and start to be charged, and when has completed the charging,  even when be removed away out of PAD.

  • 0
    TI__Guru* 76066 points
    Detection of the RX removed---TX will need to receive communications packets from the RX to continue power transfer. The TX will stop power transfer 1.5 sec after communications with RX stops. Most RX will send a communications packet every 250mS.

    Charge complete is different -- The RX must tell the TX that charge is complete and End Power Transfer 01 (EPT01) is used. This will put the TX in a low power state, it will wake up at check if RX is still present and needs to resume charging.
  • 0 in reply to Bill Johns
    Prodigy 50 points
    When TX has been in a low power status, it still is keeps receiving the communication packet from RX in case of recharging request.

    But how can "I" or my MCU know the device (RX) is removed away the PAD after TX has been in sleep mode, though I know TX really could know.
    Can I read this change via I2C interface by a external MCU? or check the transation (0->1, 1->0) in any pin on TX.
  • 0 in reply to Jacky Wang23
    TI__Guru* 76066 points
    The I2C bus can be used to monitor device performance and determine if the RX is present. See SLUA767 on ti.com.
  • 0 in reply to Bill Johns
    Prodigy 50 points

    Thanks a lot.

    I'll go to see it at once.