lp8758-B0: enabling buck 1, 2, and 3

Eric Steimle

Part Number: LP8758-B0
Other Parts Discussed in Thread: LP8758-E0

The documentation talks all about enabling buck regulator 0 by setting the correct bits in BUCK0_CTRL1. Will this enable the other three buck regulators as well? I didn't see that stated in the docs but I'm assuming it will. There is no BUCK1_CTRL1, BUCK2_CTRL1, or BUCK3_CTRL1 registers although there are four BUCKX_CTRL2 registers for setting the current limits.

The register addressing also skips by one value exactly where you would expect those missing registers to be for example:

0x02 - BUCK0_CTRL1

0x03 - BUCK0_CTRL2

0x04 - undefined

0x05 - BUCK1_CTRL2

I just want to know how to turn on all the regulators and if I can turn them on one at a time or not.

Thank you,

over 8 years ago

0 Brian Berner over 8 years ago

TI__Mastermind 30280 points

Thank you for posting your question on the LP8758-B0 in the e2e forum. Your thread has been assigned to the expert within TI, who will reply to your question as soon as possible and attempt to resolve your issue.

0 Jari Niemela13 over 8 years ago in reply to Brian Berner

TI__Genius 13850 points

Hi Eric,

On LP8758-B0 configuration bucks 1, 2 and 3 are slaves for the buck 0. This means that enabling buck 0 will be enough. Based on output load current the buck 0 will enable slave bucks one by one to support needed current.

Bucks 1, 2 and 3 CTRL1 registers are reserved since buck 0 will override them and any settings to these register will not affect functionality in -B0 configuration.

Best regards,
Jari Niemelä

0 Eric Steimle over 8 years ago in reply to Jari Niemela13

Expert 2290 points

Thanks Jari, I see now that we meant to use the LP8758-E0.

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lp8758-B0: enabling buck 1, 2, and 3