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LM5001-Q1: How to calculate the output current according to input current?

Part Number: LM5001-Q1

I have an application using LM5001-Q1 to generate 60V out of 12V and need to deduce the current in 60V power rail from 12V input.

I measured the 12V power rail current before and after I applied the load and the difference is 240uA(15.465mA-15.225mA), which means the load at 60V consumes 48uA assuming 100% efficiency. But when I measure the 60V current directly, it is 51uA.

This is strange, because this indicates the boost's efficiency is more than 100%.

So is the boost itself consumes power differently before and after adding 50uA load on the 60V power rail?

  • Hello,

    Input current can be estimated by the following (note this is assuming 100% efficiency).

    IIN = (VOUT/VIN)*IOUT

    All these measurements should be one with an DMM that has good accuracy with the current range (uA) that you  are trying to measure. The input and output voltages should be measured directly and the input and output terminals of the board.

    Garrett