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TLV733P: Efficiency information

Dar
Prodigy 100 points
Part Number: TLV733P

Hello,

I would like to ask if anyone have an information with regards to the efficiency of this particular part, TLV73333PDBVT.  Seems like it is not included in its technical datasheet.

Thanks!

  • 0
    TI__Guru 55940 points
    Hi Dar,

    The efficiency for a linear regulator will depend on the application conditions. Efficiency is power in divided by power out; therefore, the lower your headroom (Vin - Vout) the more efficient your application will be.

    Very Respectfully,
    Ryan
  • 0 in reply to Ryan Eslinger
    Prodigy 100 points
    Thanks Ryan.

    I have actually captured data already for my operating Vin-Vout. I may just need to have a benchmark to compare with my actual measured values.
  • 0 in reply to Dar
    TI__Guru 55940 points
    Hi Dar,

    First I must apologize, I had a typo in my statement, I meant to type power out divided by power in.

    I need more information about your application to help you calculate your application efficiency. What is your Vin, Vout, and Iout?

    Very Respectfully,
    Ryan
  • 0 in reply to Ryan Eslinger
    Prodigy 100 points
    No worries Ryan

    It's 5V to 3.3V. For the Iout, it would be best to have info for 0mA to max operating current.
    Thanks again.
  • 0 in reply to Dar
    TI__Guru 55940 points
    Hi Dar,

    As stated above efficiency is power out divided by power in. Since power is voltage multiplied by current we can use the following calculation:

    efficiency = (Vout x Iout) / (Vin x Iin)

    Since Iin is equal to Iout + Ignd we can substitute to get:

    efficiency = (Vout x Iout) / (Vin x (Iout + Ignd))

    At no load your efficiency will be 0 since no power is delivered to your load. At full load (300 mA) you will have the following:

    efficiency = (3.3 V x 0.3 A) / (5 V x (0.3 A + 0.00006 A))
    ***Note I used Figure 14 from the datasheet to see that Ignd is 60 uA at 300 mA load at 25 C

    efficiency = 0.99 W / 1.5003 W
    efficiency = 0.6599 or 65.99%

    If you were to reduce your headroom, you would improve your efficiency.

    Very Respectfully,
    Ryan
  • 0 in reply to Ryan Eslinger
    Prodigy 100 points
    Thanks Ryan