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LM2596: Adding LDO for Adjustable output

Anonymous
Anonymous
Part Number: LM2596


How do you add a LDO to the output of the adjustable version of the LM2596 and still be able to get a adjustable output for the overall circuit adjustable via a potentiometer or something like that?

  • Hi Andy,

      I'm not sure if I've understood your question; but I guess what you want is to add a LDO to the output of the buck converter for better DC output; and you also want to use a potentiometer to get both converter and LDO output change with same dropout voltage, right?

      Please let's know more details about your application, so, we may give you better solution.

     Thanks!

     Phil

     

  • Anonymous
    0 Anonymous in reply to Phil Yi
    Yes, I think they would need to change in relative synchronization as in changing at a fixed and relatively linear rate relative to each other; precise timing would not be super important as long as they were within a few seconds of each other if that would make much of a difference and this is for a benchtop supply with details minimally worked either a pushbutton digital pot or manual would work.
  • Hi Andy,

      From what you said, I think it's about overall system design for bench-top power supply; it's a little beyond of part application support.

      Please let's know if you have questions about the device itself.

    Thanks!
    Phil

  • Anonymous
    0 Anonymous in reply to Phil Yi
    As a general way to add a LDO and have a adjustable output of both while still having the same voltage dropped by the LDO with a dual ganged potentiometer (used as a rheostat) for two adjustable devices with the same Vref and the same resistor to ground adding a fixed resistor of a appropriate value in the LM2596 feedback path between the potentiometer and the feedback input/resistor to ground or if the LDO is table with a ~0.6V drop adding small signal diode ie 1N4148 or for a LM285LP-1-2 for a ~1.2V and stable drop?