Hi
The datasheet mentioned when an open load/short to battery happen in the off state, the CS pin will pull up to Vcs,h. Why will the CS pin been pull up to Vcs,h considered the CS pin is a reflection of the current flow through the the channel and equals to zero when a open load happened?
Can you help me to understand below circuit and help elaborate on how this circuit is functioning here? I don't not really understand the datashee here, See below datasheet comments and my questions.
Thus, TI recommends an external pullup resistor to offset the leakage current. -- How this pull up resistor will help to offset the leakage current?
This pullup current should be less than output load current to avoid misdetection in the normal operation mode. -- I don't understand.
To reduce the standby current, TI recommends to always use a switch for the pullup resistor. TI recommends Rpu ≤ 15 kΩ. -- I don't understand either.