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BQ24133: BQ24133RGYR

Tirthal patel
Intellectual 460 points
Part Number: BQ24133

Hello,

We are using BQ24133RGYR in our application,our application is based on driving the small heater rated V=12V and P=35W. In our system the battery will be always plugged in.Adapter will only be used it when it needs charging /charging and driving load.

We are using battery rated 12V and 5000 mah. With charging current of 2 A and discharge rate of 1C.

 Query related to BQ24133RGYR charging IC is mentioned below :

1)When i plug in the charging adapter from which path of charging IC  will power my System...?

2)When adapter is not there then which path of charging IC provide power to the system.?

3)If my system works on the Charging adapter ,then what will happen if my load consumes more power than the Charging  adapter output...?(Note : Also need to charge the battery when charging adapter is plugged in)

4)What is the use of BATDRV pin of IC that connedt to P-mosfet...???

I am attaching a document for the schematic...!!

 

  • 0
    TI__Guru**** 166046 points
    Hi Tirthal,

    Regarding 1, with adapter plugged in, the system is powered from the adapter through Q6 and Q7. Your schematic shows the same net name (VCC_CHG_15V) before and after Q6, Q7 and R201, thereby shorting out the FETs and current sensing resistor. Please changing the system side net name.

    Regarding 2, with adapter removed, the system is powered from the battery (VCC_BAT_12V) through PMOS Q9.

    Regarding 3, this charger has IDPM feature which will reduce charge current to zero when the input current, measured through R201, exceeds the set point. Q9's diode prevents the system from dropping below the battery voltage.

    Regarding 4, /BATDRV turns on Q9 fully when the system voltage drops to the battery voltage as sensed at the SRN pin.

    I noticed in your schematic that TS pin is floating, which will prevent the charger from charging the battery. If the TS function is not used, please add a resistor divider from VREF to GND using equal sized resistors.
  • 0 in reply to Jeff F
    Intellectual 460 points

    Hello,sir

    Thank you for your prompt reply..!!

    Regarding 1-The net at the Charging adapter side is( VCC_CHG_15V) and after the sense resistor net name is (VDD_SYS_15V).

    So at the time when charging adapter is plugged in, the Power path will be through (VDD_SYS_15V).is this so .?

    Regarding 2-So when charging adapter is plugged in ,the supply will be through (VDD_SYS_15V) and when my Charging adapter is not present the supply will be through VDD_BAT_12V. So, i need to keep both the net (VDD_SYS_15V ) and (VDD_BAT_12V) as input to my system ..?

    Or Is there any common Power net that deliver the power to the system i.e to my load.

    Regarding 3-Ok understood when the Charging adapter is not capable to  match up for delivering the power to the system it reduces the charging current of the battery so that it can match the power requirement of the load with the help of IDPM feature.

    I want to ask one more thing ,

    1)My load works on the 12 V rating ,i am providing the 15 V to the system input through the charging adapter,so is there any way that i can set the charging adapter voltage to 12 V.

    Will my charging adapter voltage 15 v work as the system input(Load input) voltage when the charging adapter is plugged IN..?

    Regarding 4-My system voltage means my charging adapter voltage ,("system voltage drops to the battery voltage") means Charging adapter not plugged IN..?

    I added the 10k(0402) resistor R230 and R231 from the Vref Pin to GND ob the TS pin.Ok done.

    Is it necessary to keep the D15 diode at the Charging adapter side ,In our application the battery is always plugged in the PCB.

    Why it is necessary to provide 2 Power supply at D15 input ..?

    Will my charging IC be off when charging adapter is not plugged IN....?

    Waiting for your reply..!!!

    I am attaching schematic.

     

  • 0 in reply to Tirthal patel
    TI__Guru 57371 points
    Hi,

    The thread has been quite for a while. It is considered solved and closed.

    Thanks!