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TPS7B7702-Q1: TPS7B7702-Q1 Max power dissipation/current

Gerard Copeland
Genius 10490 points
Part Number: TPS7B7702-Q1

Hi, 

To calculate the TPS7B7702-Q1 Max output current, could we use below formula?

Max power dissipation: PD(max) = （TJ(max)-TA）/ θJA;

Max output current: Iout(max)= PD/( Vin – Vout)

 

For above max power dissipation /current, is it for total 2 channel? Or single channel?

If it is for total 2 channel, the max power dissipation per channel should be PD(max)/2 ?

Thanks,

Gerard

  • 0
    TI__Guru 55940 points
    Hi Gerard,

    You are correct that until you have your own layout, the best method to estimate the maximum output current is to use the equations that you state. The Thermal Information table in the datasheet is populated by data modeled on the JEDEC Hi-K board in order to provide a standardized layout for comparison.

    Layout is critical in determining the thermal performance for a linear regulator. The primary heatsink for TPS7B7702-Q1 is the GND plane of the PCB local to the LDO. As such, you will achieve your best thermal performance by maximizing the GND copper local to the LDO.

    The maximum power calculation will be for the total power dissipated in the LDO. As such, you will want to calculate the combined power dissipation for both channels of this dual LDO.

    Very Respectfully,
    Ryan