Hi all:
I used about 1A discharge, CC_HI=0XFF, CC_LO=0XE3, according to the datasheet formula on page 23
CC Reading (in µV) = [16-bit 2’s Complement Value] × (8.44 µV/LSB)
It was calculated as 29*8.44=244.76 V, and the sampling resistance was 0.0005 ohm
The calculated current is 0.4895A
This result is half different from the actual current. Is there any problem with my algorithm?