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TPL7407LA: Pull up resistor for driving resistive loads

Part Number: TPL7407LA

Hi,

I'm looking to use the TPL7407LA to drive peripherals, one peripheral being a dc heater. In the datasheet it says for resistive loads:

'When driving a resistive load, a pull-up resistor is needed in order for the TPL7407LA to sink current and for

there to be a logic high level. The COM pin must be supplied ≥ 6.5 V for full functionality'

Would like to know what is meant by needing a pull-up resistor to sink the current and the placement and value of the resistor in the circuit.

Thank you,

Sean

  • Hi Sean,

    Thanks for reaching out on E2E!

    The wording in the statement is a bit confusing. Simply, all it means is that the resistive load needs to be connected from the input supply to the output pin of the TPL7407LA. In addition, the COM pin should also be connected to the same input supply.

    Thanks,
    Arthur Huang