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UCC28634: How to use the double power function of UCC28634?

Part Number: UCC28634

    From the datasheet of UCC28634:"The peak power mode allows transient peak power delivery up to 200% of nominal rating, with only a 25% peak current increase, maximizing transformer utilization" .we can know the UCC28634 has double power function.

When UCC28634 go into double power,the switch frequency can greater than 60KHz,the Vcs is between 0.64V and 0.8V.

    So i make a experiment:the output voltage of load is 27V.I make the current of load change from 1A to 9A.The 9A duration time is 0.2S.The 1A duration time is 1.8S.In the other word,the period is 2S,and the duty is 10%.I can get the following waveforms:

  

The green waveform is current of main winding.The blue waveform is voltage of output.we can see the voltage of output can be hold on when the current of load change to 9A.And the switch frequency can greater than 60KHz.So i can sure the ucc28634 went into the double power region.

Then I increase the load,I change 9A to 10A.I can get the following waveforms:

The voltage of ouput is drop down.And the switch frequency don`t increase.So i don`t know why?

In my opinion,the Vcs and the switch frequency will increase when the load increase in the double power region.But the adjustment speed of ucc28634 seems too slow,led the voltage of output drop down.

here is my schematic:

Thanks.

  • Hi

    I'd like to clarify a comment you made first. When you mention "When UCC28634 go into double power,the switch frequency can greater than 60KHz,the Vcs is between 0.64V and 0.8V" do you actually mean 120kHz? 60kHz is at 40% Pnom, 120kHz is at 100% Pnom.

    It appears that the output voltage is decreasing as you attempt to deliver 10A load. What is the maximum power (200% Pnom) limit of your design? Please note that this is the maximum point that UCC28634 can deliver power, so when the load attempts to pull more current the output voltage will decrease since the controller cannot provide any more power.

    I recommend measuring the voltage at CS pin to confirm this. UCC28634 will limit the voltage on this pin to 800mV. Based on the waveforms you provided, it looks like you are at 656mV with 9A load (6.56A*0.1ohm), so you are close to this limit with the power level that works. You can deliver more power by decreasing the current sense resistor (R69 in your schematic).

    Best Regards,
    Eric
  • Hi

    I'd also like to add one clarifying comment, the max frequency that UCC28634 can operate at is 150kHz. UCC28634 operates in a variable switching frequency mode in this range, so it increases the switching frequency to deliver more power. If the frequency is at 150kHz then it cannot increase further to deliver more energy. I also recommend measuring the switching frequency between 9A and 10A load to see if this limit is also reached.

    Best Regards,
    Eric
  • Hi Eric

    You mean that  the 800mV voltage limit on the CS pin limit the load?So I change the current sense resistor from 0.1R to 0.05R,I get the following waveform:

        The max current of load can increase to 16A now.The output will drop down again when  I continue to increase the load current.But the main winding's max current is 9.04A,so the Vcs=0.05R*9.04A=0.452V.So this time I can sure the CS pin voltage doesn`t reach to the 800mV.Why the output voltage drop down again?

        The biggest switch frequency is 60KHz and the biggest voltage on CS pin is 450mV,so I can sure the ucc28634 doesn`t go into the double power region.If I want to get more load current ,what can i do? How can I make the ucc28634 go into the double power region?I can get the 16A load current when ucc28634 don`t go into the double power region.If the ucc28634 can be into the double power region,can i get the 32A load current?

    thanks

  • Hi

    UCC28634 is operating correctly here. From your waveforms it is clear that the converter is operating in CCM. When the FET turns on the current is not a 0A, so it's in CCM. This means that you are in the overpower state (Pnom > 100%). When you reach the 16A limit you are at Pnom = 200%. If you want more load current, continue to reduce the current sense resistor. As your last change showed, when you decreased it the current limit increased from 10A to 16A, so if you reduce it further you'll be able to provide more output power.

    Best Regards,
    Eric
  • Hi
    But as you can see,the switch frequency limit at 60KHz when the current sense resistor decrease to 0.05R.From the Figure 41 of the ucc28634`s datasheet,the switch frequency will greater than 60KHz,Is the ucc28634 really be in double power region? What can i do if I want the ucc28634 work at 120KHz?
  • Hi Eric:
    But as you can see,the switch frequency limit at 60KHz when the current sense resistor decrease to 0.05R.From the Figure 41 of the ucc28634`s datasheet,the switch frequency will greater than 60KHz,Is the ucc28634 really be in double power region? What can i do if I want the ucc28634 work at 120KHz?
  • Hi Eric:
    But as you can see,the switch frequency limit at 60KHz when the current sense resistor decrease to 0.05R.From the Figure 41 of the ucc28634`s datasheet,the switch frequency will greater than 60KHz,Is the ucc28634 really be in double power region? What can i do if I want the ucc28634 work at 120KHz?
  • You need to design the transformer inductance as well as other things for full load power at about P4 which also with 60kHz. After you achieve this design goal, the 2x peak power can be obtained.

    There are two constraints for design to check in order to operate rated power at P4. The two constraints are based on Equation (15) and (16), page 31 of the datasheet.

    You can also use UCC2863x calaculation tool to help your design and check the two constraints. The tool can be downloaded from this link
    www.ti.com/.../sluc537