We want to design and guarantee that the TPS61090 can start up reliably when there is an input current limit. Although it has been known that the system can be started without any problem in the actual machine check, the output waveform does not operate as the data sheet because of the current limitation. In order to explain this operation, could you tell me the principle of operation of this IC at startup?
Thank you for your coopration.
<Background of questions>
The INPUT of the TPS61090 is powered by USB. In order to conform to the USB 2.0 standard, a 500 mA current limit is applied. Since the voltage is lowered by the USB cable, the input power of TPS61090 becomes about 4V. I want to boost this 4V to 5V.
However, since the INPUT current is limited to 500mA, it behaves like the attached waveform. Probably, if there is no limit on the INPUT current, the output voltage starts up smoothly to 5 V, but due to the lack of current and the voltage shortage, it does not start smoothly and the output voltage drops once.
I do not need to be smooth, but I want to guarantee that I can always output 5V, but I can not explain the fact that it starts up absolutely because I do not know the operation principle at the time of startup of TPS61090. Input power> output power, so I think that it will start without problems. Could you tell me the starting principle of this IC?
[Electrical Schematic of Circuit Board]
[Wavefrms]