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BQ25890: Device thermal runaway under 5A load

Part Number: BQ25890

I am working to integrate part BQ25890 as part of a student project. The device manages a single 18650 and powers a device requiring 5A continuous current. I have followed TI's reference design and layout guidelines and upon testing the board under load have experienced some problems. After drawing 4.5A for about 10 seconds the device shuts off, I believe due to thermal shutdown but I am not positive as I only had a handful of times to test. After testing this behavior a few times the device now shuts off instantly when any significant power is drawn (>500mA). The resistance between BAT and SYS is now 75 ohms. There are no faults reported and I can still communicate via I2C. 

I've followed TI's reference design from the datasheet and have included PDFs of my layout and schematic.  Please let me know if you see any issues or if I just need to heatsink the chip more carefully.  I am certain that the rest of the board can handle the current, as I have tested the device under load simply supplying voltage to the SYS pins and there are no thermal issues.  From my calculations my 5A load should produce about 0.5W of heat, according to an Rgs(BATFET) of 19mOhm.  

The physical board is 1oz copper with 2 layers.  I am certain there are no shorts or mechanical issues with the board and was careful during the reflow process to rework anything wrong with the board before powering it.  It works perfectly fine just powering the microcontroller and OLED, only when I apply load does the SYS voltage drop.  I have also attached pictures of the behavior on my scope - the green channel is voltage to the gate of the MOSFET controlling the load and the yellow channel is SYS voltage.  You can see that the device very quickly responds to the load and SYS voltage recovers when the MOSFET shuts off.

Thank you kindly.

PCB_SCH.pdf

PCB_TOP.pdf

PCB_BOT.pdf

  • Hi Robert,

    Regarding your thermal calculations, you are correct in that the losses are RDSon(batfet)*ISYSload in battery only mode. When powered at VBUS, from Po/Pi=efficiency and Pi-Ploss=Pout you can compute Ploss. Using Ploss and RthetaJA, you can estimate the losses. RthetaJA assumes a board with 2oz copper and large, unbroken ground plane for the thermal pad to via. On your layout, with 1oz and the broken up ground plane on the bottom, I suspect the device is hitting either thermal regulation, where it reduces output current to reduce IC temperature, or thermal shutdown. Do the I2C status register report thermal regulation?

    At room temperature and VBUS = 7 to 9V, the BQ25890EVM with 2oz copper and larger, unbroken ground plane can provide 5A output.

    Regards,
    Jeff
  • Robert,

    One more comment about the EVM, it is 4 layers and uses an internal layer as well as bottom layer for ground and therefore heatsinking.

    Regards,
    Jeff
  • Jeff,

    Thanks for confirming.  I realized I made a typo and meant RDS instead of RGS but you seem to have corrected my mistake.  Anyway the 0.5W dissipated only helps slightly, since the thermal characteristics assume that my ground plane is as good as the test coupon used.  I've confirmed this suspicion through http://www.ti.com/lit/an/spra953c/spra953c.pdf.  PCB design has a huge impact on the thermal constants.

    As for faults there were none when I last tested but I will confirm when my sample order arrives and I can replace the dead chip. I can't change the board until my next revision but even then may not be able to switch to a 4 layer board (although my current design is tight with only 2 layers considering the largely broken ground plane).  I can heatsink the IC through the aluminum enclosure.  Will the IC dissipate enough heat through the top of the package? 

    I am not nearly as worried about charging or operation from VBUS as I am limiting charge current to 1A and the 5A drawn would exceed the connector I've placed on the board for charging.  

    With appreciation,

    Robert

  • Robert,

    Very little heat gets out through the top of the IC.  The QFN package relies on its thermal pad and vias to other planes to work.  I have used this IC at room temperature up to 5A with VBUS=7-9V and it will get hot but should work or self protect in thermal regulation. 

    Regards,

    Jeff

  • Jeff,

    Thanks.  I'll see when I get the samples in and replace the IC.  There's not much I can do about the ground plane at the current moment but maybe heatsinking the top of the package can extract some heat. As you mentioned the top is a very good insulator so I don't think this will be as effective as increasing copper weight or number of ground planes.  The device will be drawing 5A continuously for up to half an hour so heat is of great concern. If the device limits current or enters thermal shutdown the voltage drop will be great enough such that the LDO for the microcontroller stops outputting.  Another solution I am considering is to have the load powered from VBAT and the microcontroller from SYS.  This way the only other resistance is that of the MOSFET.

    Robert

  • Robert,

    If charge is enabled, the buck converter will still operate to provide current through SYS to BAT and BAT's load.

    Regards,
    Jeff
  • Hi Jeff,

    The samples came in and I was able to replace the IC to replicate my issue.  When I attach a dummy load of 1 ohm to SYS and only power the device through BAT after some time the device again ceases to work.  The REG10 bit 7 isn't flipped but the IC gets very hot.  After some time with the load attached (and drawing 4-5A) BATFET is disabled (REG09 bit 5).  After this behavior starts BATFET is instantly turned off when the load is attached.  

    What's strange is that the MOSFET also dissipates a similar amount of heat and hardly heats up at all - in fact, I've left the MOSFET on with the load attached for up to an hour and it hardly gets hot.  Please let me know if you have anything else that I can troubleshoot in case my issue is somehow unrelated to thermal performance.  I may simply need to move to a second revision where I revise the layout to improve thermal performance.  However, I would like to confirm that this is in fact the underlying issue first.

    Kindly,

    Robert

  • Robert,

    Can you order an BQ25895EVM and test on it? There must be something else wrong with your board. I do not expect this behavior with 4-5A.

    Regards,
    Jeff
  • What is the current rating of your inductor? Needs to be higher than your load current if using 5V input.

    Regards,
    Jeff
  • My inductor is rated for 6.5A and the saturation current rating is 7A.  The part is an Eaton MPI4020V2-1R0-R.  I can potentially order an eval board but it will be difficult to hook it up to my circuit without bodging a number of wires. Nevertheless, if you suggest that's where I troubleshoot next I can see if this is possible without ordering a board specificically for testing.

    Robert

  • Also, while testing I am only powering the device with 4V on BAT and no voltage on VBUS.
  • Robert,

    We can try to debug why your board's efficiency is so low.  If you load with SYS with a 5 ohm resistor and 5V on the input and maximum input current limit, what is the efficiency (Vsys*Isys)/(VBUS*Ibus)?  Should be in the ~ 90%. As you increase the load on SYS with 5VBUS, you will eventually need to start supplementing through the battery FET.  If you increase VBUS to approx 7V (as measured close to ICs VBUS pin), the charger should be able to provide the entire 5A load on SYS regulating to 3.7V (3.7V*5A/7V*3.25A) = 81%.   with Po+Ploss=Pin and Po/Pin=0.81 you can find Ploss which is the power that the IC and the inductor must dissipate.  Inductor losses are approximately DCR*ISYS, ignoring ripple. 

    Regards,

    Jeff

  • Jeff,

    I can certainly try that this evening. However my input current limit is 500mA in real device operation and the device senses the presence of a charger and disables the load as most times I'll be charging off of a standard USB output. I'm most concerned with the behavior of the system when powered from the battery and to my understanding the converter only runs when the battery voltage drops below minimum system voltage.

    Thanks
  • Robert,

    With VBUS applied, the converter runs all the time to provide load to SYS unless you disable the entire chip with HiZ bit. I assume there are long periods where the system load is not present so your battery can recharge?

    Jeff
  • Yes. During charging the large load is disabled and only the microcontroller runs to signal charge status to the user.
  • Robert,

    The thermal shutdown shutdown circuitry only impacts the buck converter. I now agree that the heat generated from the losses across the BATFET is not being dissipated by the powerpad through the board. My only suggestion, without relaying out the board, is to use airflow across the top and especially the bottom of the board.

    Regards,
    Jeff
  • Hi,

    We haven’t heard back from you for a while, the thread is considered solved and closed.

    Thanks,

    Ning.