Hi
We are considering heat sink for LM338 (TO-220).
We uses following equations.
Vin = 12V
Vout=4.5V
Io=0.7V
Ta=60C
Tj=125C
Iq = 3mA as maximum ( According to Figure 9 )
Pd = (Vin - Vout) * Iout + (Vin * Iq) = 5.28W
Tj = Ta +(Rjc + Rcs + Rsa) * Pd -> (Rcs+Rsa) = (Tj-Ta)/Pd - Rjc = 12.3 - 15.7 = negative value ?
Could you please tell me how to calculate heat sink thermal resistance correctly?
BestRegards