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BQ40Z80: BQ40z80 GPIO question

Part Number: BQ40Z80

Hi there

Our customer want to use BQ40z80 pin17(PRES/SHUTDN/DISP/PDSG/GPIO)  GPIO function to drive a socket. Could you please give comments as following question?

1. What is the duration of the GPIO Interrupt interrupt signal? Is it possible to determine the operation result of the selected bit every 250ms and refresh the GPIO state? Because the GPIO interrupt is used to control the total power supply, it is important that the interrupt signal persists until the MCU is working properly.

2. GPIO has two output modes, one is High-Z/Driven-low and the other is Driven-high/Driven-low. Please help confirm separately:
a) What is the drive current capability of the Driven-low when in High-Z/Driven-low mode? If the drive capability is OK, prepare to pull Q7 directly from the GPIO port and MCU_OUT, and turn Q7 on. (If you can please help me see if there are other risks.)

b) When it is in Driven-high/Driven-low mode, analyze the IO port as follows. Please help us to see how the GPIO port should wake up.
                 i. Pin12/13: Since the VREG is typically 1.8±0.2V, it is not possible to directly drive the 3.3VMCU;
                Ii. Pin15/16/17: Only the output voltage high limit voltage is specified in the specification, and the upper limit and drive capacity are not explained.
               Iii. Pin20/21/22: Output voltage high=Vbat-1.6V, and the output voltage is more than 20 volts.

BR,Eason

  • HI Eason,

    1. The GPIO signal is just a level signal. It needs to be asserted at least 1s.

    2. Vol Imax is 1.5mA, if you try to pull more current from that you will grey out the IC

    2b1, that is correct, you will have to level shift the 3.3V signal

    2b2: At VOH the max current drive is -10uA, so it is very very low. Don't draw more current otherwise you risk chip grey out

    2b3 You will exceed max threshold of voltage on the pin. This will burn the IC.