Hi
I use 2 PD, and connect 2 PD's VDD to together.
The attached shows our design, there are 2 22uF cap for each PD, 10uH inductot and another 2 39uF caps.
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Hi
I use 2 PD, and connect 2 PD's VDD to together.
The attached shows our design, there are 2 22uF cap for each PD, 10uH inductot and another 2 39uF caps.
Hello,
Thank you for your question. We have a TI Reference Design that is similar to this configuration. In our schematic, we populate both RMPS resistors:
http://www.ti.com/lit/an/slva986/slva986.pdf
The advice I gave above is for combined power to get more than 90W of power. In order to give the best advice moving forward, I need to understand what is trying to be accomplilshed. Is the goal to use UPoE, go beyond BT PoE, use two lower power PD's, have two for redundancy?
Please correct me if I am wrong, but this schematic appears to be the same project as this post:
https://e2e.ti.com/support/power-management/f/196/p/830547/3072801#3072801
Can you confirm?
Currently I am working with Richard Yang on this project. Thank you!
Regards,
Michael Pahl
Hello,
Thank you for letting me know you are looking for a BT 90W solution.
My understanding of your schematic is that you will need both RMPS_DUTY resistors. 1.3K resistor should be fine, but it is calculated with equation 3 in this PDF: http://www.ti.com/lit/ds/symlink/tps2372.pdf
For your second question, yes you will need the diodes. They provide protection from the circuitry. When one PD turns on, if the other does not have the diode it could damage the PSE. However, I will note this drives efficiency down.
Can you please explain why you want two PD devices? One TPS2372 can be a class 8 PD, and the diodes would not be needed.
Regards,
Michael Pahl
User4206464, It has been nearly a week without a reply from your side. Do you consider this thread closed?
Thanks,
User4206464,
It has been 10 days since you have corresponded with us. As such, we are going to consider this matter resolved and close the thread.
Please reply if that is not accurate (a reply with automatically re-open the thread).
Thanks,